Tuesday, November 12, 2019
Lab Report: Specific Heat :: essays research papers
Introduction   	The porpoise of these is to determine the Specific Heat. Also known as Heat Capacity, the specific heat is the amount of the Heat Per Unit mass required to raise the temperature by one degree Celsius. The relationship between heat and temperature changed is usually expected in the form shown. The relationship does not apply if a phase change is encountered because the heat added or removed during a phase change does not change the temperature.            			                             Q = cn^T    	The molar specific heats of most solids at room temperature and above are nearly constant, in agreement with the Law of Dulong and Petit. At lower temperatures the specific heats drop as quantum processes become significant. The Einstein-Debye model of specific heat describes the low temperature behavior.         The metal samples are:  à ·	Copper (CU)  à ·	Aluminum (Al)  à ·	Zinc (ZN)  à ·	Tin (Sn)  à ·	Lead (Pb)  à ·	Steal/iron (Fe)  à ·	Brass (an alloy of Zn and Cu)  PROCEDURE:  1.	        In a Styrofoam cup, record the temperature of the 200 ml of cold water. This is 200 g of water, as the density of water is 1 g/ml.  2.	       Obtain a sample of metal that has been immersed in boiling water and place it in the cup of water.  3.	        Wait until the temperature no longer rises (thermal equilibrium), and record the temperature increase.  4.	        Discard the water and measure the mass of the metal.  5.	        Repeat the above for each metal.             CALCULATIONS:  1.	H=mc^T=(200g/1)(1cal/goc)(2oc/a)=400cal  C=H/m^T=400cal/(128g)(20c)=1.5625cal/goc  2.	H=mc^T=(200g/1)(1cal/goc)(2oc/1)=400cal  C=H/m^T=400cal/(20.1g)(2oc)=400cal/40.2 goc=9.95cal/ goc  3.	H=mc^T=(200g/1)(1cal/goc)(2oc/1)=400cal  C=H/m^T=400cal/(53.9g)(20c)=37.38cal/ goc  4.	H=mc^T=(200g/1)(1cal/goc)(2oc/1)=400cal  C=H/m^T=400cal/(65.3g)(20c)=3.06 cal/ goc  5.	H=mc^T=(200g/1)(1cal/goc)(2oc/1)=400cal  C=H/m^T=400cal/(70.5)(20c)=400cal/141goc=2.83 cal/ goc  6.	H=mc^T=(200g/1)(1cal/goc)(2oc/1)=400cal  C=H/m^T=400cal/(70.1g)( 20c)= 2.83 cal/ goc  7.	H=mc^T=(200g/1)(1cal/goc)(2oc/1)=400cal  C=H/m^T=400cal/(50g)(20c)=4 cal/goc  RESULTS:  Type of Metal	Experimental à © of Metal 	Actual à © of Metal  CU  	400cal	1.5625cal/goc  Al	400cal	9.95cal/ goc  ZN  	400cal	37.38cal/ goc  Sn	400cal	3.06 cal/ goc  Pb	400cal	2.83 cal/ goc  Fe		400cal	2.83 cal/ goc  Brass 	        	400cal	4 cal/goc    					    
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